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replaceAll(listToCheck, findPattern, replacementString)

ArgumentTypeDescription
listToCheckString or Array 
List
A string (or list of strings) to evaluate.
findPatternRegular ExpressionPattern to be matched in listToCheck
replacementStringStringString to replace matching pattern in list

Examples

replaceAll(in.fileName, "[0-9]{8}", "")

...

If in.fileName = "20060712file-proc20070103-1263", this returns "file-proc-1263".


replaceAll(in.BudgetCode,"\\\\","")

This expression removes any backslashes ("\") in the string "in.BudgetCode" e.g. if in.BudgetCode is "323\-ABC", the value returned is "323-ABC". The reason that multiple backslashes are used is because "\" is an "escape" character in a Regular Expression. This allows special control charaters to be treated as regular characters. See Regular Expression for more details. 

See Also