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replaceAll(listToCheck, findPattern, replacementString) Replace all occurrences of a pattern with a replacement string. |
Function: replaceAll()
Replace all occurrences of a pattern with a replacement string.
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replaceAll(listToCheck, findPattern, replacementString)
| Argument | Type | Description |
|---|---|---|
| listToCheck | String or Array |
| A string (or list of strings) to evaluate. | ||
| findPattern | Regular Expression | Pattern to be matched in listToCheck |
| replacementString | String | String to replace matching pattern in list |
Examples
replaceAll(in.fileName, "[0-9]{8}", "")
replaceAll() removes all strings of 8 digits from file names contained in the attribute in.fileName.
If in.fileName = "20060712file-proc20070103-1263", this returns "file-proc-1263".
replaceAll(in.BudgetCode,"\\\\","")This expression removes any backslashes ("\") in the string "in.BudgetCode" e.g. if in.BudgetCode is "323\-ABC", the value returned is "323-ABC". The reason that multiple backslashes are used is because "\" is an "escape" character in a Regular Expression. This allows special control charaters to be treated as regular characters. See Regular Expression for more details.