Function: replaceAll()
Replace all occurrences of a pattern with a replacement string.
Syntax
replaceAll(listToCheck, findPattern, replacementString)
| Argument | Type | Description |
|---|---|---|
| listToCheck | String or Array | A string (or list of strings) to evaluate. |
| findPattern | Regular Expression | Pattern to be matched in listToCheck |
| replacementString | String | String to replace matching pattern in list |
replaceAll applied to:
- a multielement array returns a multielement array
- a single element array returns a string.
Examples
replaceAll(in.fileName, "[0-9]{8}", "")replaceAll() removes all strings of 8 digits from file names contained in the attribute in.fileName.
If in.fileName = "20060712file-proc20070103-1263", this returns "file-proc-1263".
replaceAll(in.BudgetCode,"\\\\","")
This expression removes any backslashes ("\") in the string "in.BudgetCode" e.g. if in.BudgetCode is "323\-ABC", the value returned is "323-ABC". The reason that multiple backslashes are used is because "\" is an "escape" character in a Regular Expression. This allows special control charaters to be treated as regular characters. See Regular Expression for more details.